5x^2-20x+50=0

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Solution for 5x^2-20x+50=0 equation:


Simplifying
5x2 + -20x + 50 = 0

Reorder the terms:
50 + -20x + 5x2 = 0

Solving
50 + -20x + 5x2 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '5'.
5(10 + -4x + x2) = 0

Ignore the factor 5.

Subproblem 1

Set the factor '(10 + -4x + x2)' equal to zero and attempt to solve: Simplifying 10 + -4x + x2 = 0 Solving 10 + -4x + x2 = 0 Begin completing the square. Move the constant term to the right: Add '-10' to each side of the equation. 10 + -4x + -10 + x2 = 0 + -10 Reorder the terms: 10 + -10 + -4x + x2 = 0 + -10 Combine like terms: 10 + -10 = 0 0 + -4x + x2 = 0 + -10 -4x + x2 = 0 + -10 Combine like terms: 0 + -10 = -10 -4x + x2 = -10 The x term is -4x. Take half its coefficient (-2). Square it (4) and add it to both sides. Add '4' to each side of the equation. -4x + 4 + x2 = -10 + 4 Reorder the terms: 4 + -4x + x2 = -10 + 4 Combine like terms: -10 + 4 = -6 4 + -4x + x2 = -6 Factor a perfect square on the left side: (x + -2)(x + -2) = -6 Can't calculate square root of the right side. The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.

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